Solve the indicated variable:

1. Volume of a cone: solve for h: V=¨ir^2h/3

2. Temperature formula: solve for C: F=9/5C+32

pleaseeeee help me solve these! plzzz! i have nooo idea how to do these. THANKS! =)))

your first formula should have been

V = pi(r^2)(h/3)
multiply by 3
3V = pi(r^2)h
divide by pi(r^2)
3V/(pi(r^2)) = h

in the second , multiply each term by 5
5F = 9C + 160
9C = 5F - 160
9C = 5(F - 32)
C = (5/9)(F-32)

Of course, I'm happy to help you solve these equations! Let's start with the first one:

1. Volume of a cone: solve for h: V = (πr^2h)/3

To solve for h, we need to isolate it on one side of the equation.

First, multiply both sides of the equation by 3 to eliminate the fraction:
3V = πr^2h

Next, divide both sides of the equation by πr^2:
(3V)/(πr^2) = h

Therefore, the solution for h is:
h = (3V)/(πr^2)

Now let's move on to the second equation:

2. Temperature formula: solve for C: F = (9/5)C + 32

To solve for C, we need to isolate it on one side of the equation.

First, subtract 32 from both sides of the equation to eliminate the constant:
F - 32 = (9/5)C

Next, multiply both sides of the equation by 5/9 to isolate C:
((5/9)(F - 32)) = C

Therefore, the solution for C is:
C = (5/9)(F - 32)

These are the solutions for the indicated variables in the given equations. If you have any further questions, feel free to ask!