Solve the indicated variable:
1. Volume of a cone: solve for h: V=¨ir^2h/3
2. Temperature formula: solve for C: F=9/5C+32
pleaseeeee help me solve these! plzzz! i have nooo idea how to do these. THANKS! =)))
your first formula should have been
V = pi(r^2)(h/3)
multiply by 3
3V = pi(r^2)h
divide by pi(r^2)
3V/(pi(r^2)) = h
in the second , multiply each term by 5
5F = 9C + 160
9C = 5F - 160
9C = 5(F - 32)
C = (5/9)(F-32)
Of course, I'm happy to help you solve these equations! Let's start with the first one:
1. Volume of a cone: solve for h: V = (πr^2h)/3
To solve for h, we need to isolate it on one side of the equation.
First, multiply both sides of the equation by 3 to eliminate the fraction:
3V = πr^2h
Next, divide both sides of the equation by πr^2:
(3V)/(πr^2) = h
Therefore, the solution for h is:
h = (3V)/(πr^2)
Now let's move on to the second equation:
2. Temperature formula: solve for C: F = (9/5)C + 32
To solve for C, we need to isolate it on one side of the equation.
First, subtract 32 from both sides of the equation to eliminate the constant:
F - 32 = (9/5)C
Next, multiply both sides of the equation by 5/9 to isolate C:
((5/9)(F - 32)) = C
Therefore, the solution for C is:
C = (5/9)(F - 32)
These are the solutions for the indicated variables in the given equations. If you have any further questions, feel free to ask!