Posted by jawn on Sunday, September 20, 2009 at 3:41pm.
A train is traveling up a 5.2° incline at a speed of 3.09 m/s when the last car breaks free and begins to coast without friction.
(a) How long does it take for the last car to come to rest momentarily?
(b) How far did the last car travel before momentarily coming to rest?

physics  MathMate, Sunday, September 20, 2009 at 3:48pm
Initial velocity, u = 3.09 m/s
Final velocity, v = 0 m/s
acceleration due to gravity, g = 9.8 m/s/s
Acceleration, a = g sin(5.2°)
Distance before coming to rest, S
Time to come to rest = (vu)/a
Using
v²u² = 2as
S can be found
S=(v²u²)/2a

physics  jawn, Sunday, September 20, 2009 at 4:08pm
thanks much! ^^

physics  MathMate, Sunday, September 20, 2009 at 4:22pm
You're welcome!
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