Posted by jawn on .
A train is traveling up a 5.2° incline at a speed of 3.09 m/s when the last car breaks free and begins to coast without friction.
(a) How long does it take for the last car to come to rest momentarily?
(b) How far did the last car travel before momentarily coming to rest?

physics 
MathMate,
Initial velocity, u = 3.09 m/s
Final velocity, v = 0 m/s
acceleration due to gravity, g = 9.8 m/s/s
Acceleration, a = g sin(5.2°)
Distance before coming to rest, S
Time to come to rest = (vu)/a
Using
v²u² = 2as
S can be found
S=(v²u²)/2a 
physics 
jawn,
thanks much! ^^

physics 
MathMate,
You're welcome!