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December 20, 2014

December 20, 2014

Posted by **Priscilla** on Saturday, September 19, 2009 at 5:30pm.

- trig -
**Reiny**, Saturday, September 19, 2009 at 6:18pmmultiply by (1+sinx)/(1+sinx) which is really 1, so you are not changing the value, only the appearance.

4/(1-sin x)[(1+sinx)/(1+sinx)] to get

4(1+sinx)/(1 - sin^2 x)

= 4(1+sinx)/cos^2 x

= 4(sec^2 x)(1 + sinx)

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