Sunday
April 20, 2014

Homework Help: chemistry

Posted by Some kid on Saturday, September 19, 2009 at 4:51pm.

How many milliliters of 0.418 M HCl are needed to react with 52.7 g of CaCO3?

2HCl (aq) + CaCO3 (s) >>> CaCl2 (aq) + CO2 (g) + H20 (l)

I got .00252 mL but its wrong. This is what I did:

52.7 g x (1 mol CaCO3/100.09 CaCO3) x (2 mol HCl/ 1 mol CaCO3)= 1.05 mol HCl

volume= moles/ molarity

volume= 1.05/.418 = .00252 mL

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

chemistry - How many milliliters of 0.237 M HCl are needed to react with 52.2g ...
Chemistry - Stomach acid is essentially 0.10 M HCl. An active ingredient found ...
Chemsitry - Stomach acid is essentially 0.10 M HCl. An active ingredient found ...
chemistry - Calcium carbonate CaCO3 reacts with stomach acid (HCl, hydrochloric ...
chemistry - CaCO3(s) + 2 HCl(aq) --> CaCl3(aq) + H2O(l) + CO2 It takes 19.26 ...
Chemistry 104 - What mass (in grams) of calcium carbonate is needed to react ...
chemistry - if the chemical equation is CaCO3(s) + 2HCl(aq) > CaCl2(aq) + H2O...
Chemistry - OK I just need help with two final problems that I am stuck on: The ...
chemistry - CaCO3(s)+2HCl(aq)-->CaCl2(aq)+H2O(l)+CO2 (g) How many grams of ...
Chemistry - A 0.450-gram sample of impure CaCO3(s) is dissolved in 50.0 mL of 0....

Search
Members