Posted by p on .
can you check please/
1.Rochelle purchased an appliqance that cost $815.56 with interest included. She paid $250.00 as a dwn payment and agreed to pay the remainder in 18 monthly payments. What amount will she be paying per month? =31.42
2.find the circumfrence of the circle use 3.14 as pie round you answer to one decimal place the radius is 12 ft.=75.4 ft
3.a shopping center is rectangular with dimension of 660 yd by 110 yd what is the size in acres?=15 acres
4.the cost of 36 items is $24.80 what is the cost of an individual item to the nearest cent? =0.69
5.find the lcm of 150,36,245 =
gcf of 60,24,48 =12
6 Jaque earns $8.50 per hour for overtime he earns $13.20 per hour if he works 48.5 h in a week what pay should he receive?=$464.20
7. There is a rectangular piece of land that measures 40ft by 70 ft in the middle there is a square sandbox that is 6 ft on each side the rest of the land is covered in grass what percent of the land is covered by grass rounded to the nearest tenth of a percent? 2954sq ft
8. write the following as a common fraction or mixed number in lowest terms 6.38= 6 19/50

math 
MathMate,
#1$4 correct.
#5.find the lcm of 150,36,245 =
150=2*3*5*5
36=2*2*3*3
245=5*7*7
Take the highest power of each prime factor and multiply:
2*2*3*3*5*5*7*7=44100
gcf of 60,24,48 =12 correct.
#6 Jaque earns $8.50 per hour for overtime he earns $13.20 per hour if he works 48.5 h in a week what pay should he receive?=$464.20
The question does not state the number of hours that are considered regular (at $8.50 /hr). The excess will, of course, be considered overtime.
Some consider 35 hours as regular, some 37.5, some 40. It all depends on the company or the government authority, depending on the country or the city.
#7. There is a rectangular piece of land that measures 40ft by 70 ft in the middle there is a square sandbox that is 6 ft on each side the rest of the land is covered in grass what percent of the land is covered by grass rounded to the nearest tenth of a percent? 2954sq ft
The questions requests the percent of grass cover, which is (40*70 sq.ft  6*6 sq.ft.)/(40*70) sq.ft.
Multiply the fraction by 100% and round to nearest 1/10 of a percent as required.
#8 is correct.