How many different integers can be expressed as the sum of three different numbers in the set (1,2,3,4,5,6,7)?

Can anyone explain this one to me???
Thank you!

The smallest integer that can be represented is 1+2+3=6

The largest integer that can be represented is 5+6+7=18
Every integer in between can be represented from the two above by replacement of one or more numbers.
The total number of different integers that can be represented is therefore:???

To find the number of different integers that can be expressed as the sum of three different numbers in the set (1, 2, 3, 4, 5, 6, 7), we need to determine all the possible combinations of three different numbers from this set and find the sum for each combination.

Here's how we can approach this problem step by step:

Step 1: Determine all the possible combinations of three different numbers from the set (1, 2, 3, 4, 5, 6, 7).
To do this, you can use combinations. In this case, we need to calculate the number of combinations of 3 elements from a set of 7, which can be represented as C(7, 3).

The formula to calculate the number of combinations is:
C(n, r) = n! / ((n-r)! * r!)

In this case, C(7, 3) = 7! / ((7-3)! * 3!) = 7! / (4! * 3!) = (7 * 6 * 5) / (3 * 2 * 1) = 35 combinations.

Step 2: Find the sum for each combination.
For example, one of the combinations could be (1, 2, 3), and the sum would be 1 + 2 + 3 = 6. Similarly, calculate the sum for each of the other 34 combinations.

Step 3: Determine the number of different integers among all the sums calculated in step 2.
To do this, we need to count the distinct integers without counting any duplicates.
For example, if the sums calculated were [1, 3, 5, 6, 7, 8, 9, 9], the distinct integers would be [1, 3, 5, 6, 7, 8, 9] since 9 is repeated.

By following these steps, you will be able to find the number of different integers that can be expressed as the sum of three different numbers in the given set.

Please note that I have explained the approach to solve the problem, and you may need to perform the actual calculations yourself.