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November 22, 2014

November 22, 2014

Posted by **taylor** on Saturday, September 19, 2009 at 2:33pm.

- math -
**Reiny**, Saturday, September 19, 2009 at 3:15pmTheir times running would be the same

Let the distance covered by the slower runner be x km

then the distance of the other is 10-x km

since time = distance/rate

x/6 = (10-x)/10

solve for x, then sub into x/6 for the time

(I got 5/8 of an hour)

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