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two joggers start at the same time from opposite ends of a 10-km course. One jogger is running at 6 km/h and the other is running at 10 km/h. How long after they begin will they meet?

  • math -

    Their times running would be the same
    Let the distance covered by the slower runner be x km
    then the distance of the other is 10-x km
    since time = distance/rate

    x/6 = (10-x)/10
    solve for x, then sub into x/6 for the time
    (I got 5/8 of an hour)

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