math
posted by taylor .
two joggers start at the same time from opposite ends of a 10km course. One jogger is running at 6 km/h and the other is running at 10 km/h. How long after they begin will they meet?

Their times running would be the same
Let the distance covered by the slower runner be x km
then the distance of the other is 10x km
since time = distance/rate
x/6 = (10x)/10
solve for x, then sub into x/6 for the time
(I got 5/8 of an hour)