Posted by Anonymous on .
A particle moves along the x-axis according to the equation x = 50.0t + 10.0t^2, where x is in meters and t is in seconds. Calculate the average velocity of the particle during the first 2.30 s of its motion.
Assume the particle starts at x=0.
What is the position after 2.3 s?
x = (50 * 2.3) + (10 * 2.3^2)
That's how far it has travelled in 2.3s
From there the average velocity is easy, I think