Tuesday

October 21, 2014

October 21, 2014

Posted by **help!** on Saturday, September 19, 2009 at 8:35am.

Given 4≤y≤6, find the value of y for which 2cos((2y)/3) + √3 = 0

Here's my workings:

2.666≤(2y/3)≤4

2cos(2y/3)=-√3

cos(2y/3)= -(√3)/2

ref angle: 2.6179

2y/3= 0.5236, 5.759

and i can't seem to continue, because the answers don't tally with the range i calculated. ???

the correct answer is supposed to be y=5.5

please tell me what i did wrong!

- Trigo! -
**help!**, Saturday, September 19, 2009 at 8:37amsorry, i found my mistake already.

- Trigo! -
**Anonymous**, Saturday, September 19, 2009 at 8:43amI would start this way,

cos (2y/3) = -√3/2

so 2y/3 is in quadrants II or III

the reference angle is .5236 radians

so 2y/3 = pi - .5236 OR 2y/3 = pi + .5236

so y = 3.92699 or y = 5.4978

and the value which falls in your given range of y is 5.4978 or appr. 5.5

**Answer this Question**

**Related Questions**

algebra 1 help please - 4) a student score is 83 and 91 on her first two quizzes...

Probability - Random variables X and Y are distributed according to the joint ...

probability - Random variables X and Y are distributed according to the joint ...

Algebra 2 - Solve. 4a-2≤a+1≤3a+4 4a-2-1≤a+1-1≤3a+4-1 4a-...

Math - Minimize C=7x+3y+4z 0≤x 0≤y 0≤z 100≤2x+3y+3z 120...

Math - Minimize C=7x+3y+4z 0≤x 0≤y 0≤z 100≤2x+3y+3z 120...

Healthcare Statistic - Given the following p values, which would be considered ...

Pre Calculus - sec x = -2 , π ≤ x ≤ 3π Use a calculator to...

calculus - In spherical coordinates, the inequalities 0≤ρ≤2, 3...

calc - Find the exact area of the surface obtained by rotating the curve about ...