Posted by muffy on Friday, September 18, 2009 at 9:49pm.
Determine the center and the radius of the following circle:
so I figured I'd use completing the square after putting it in standard form:
I'm not sure where to go from here.
pre-calculus - Reiny, Friday, September 18, 2009 at 9:54pm
but you didn't "complete" the square
(x^2+8x + 16)+(y^2-2y + 1)= 8 + 16 + 1
(x+4)^2 + (y-1)^2 = 25
Now we have it in standard form.
Can you take it from there ?
pre-calculus - muffy - still stuck, Friday, September 18, 2009 at 10:11pm
Ok. Do I take the square root of the whole thing now?
I've never done this before, I'm not sure if this is even right and if it is, I definitely don't know where to go from here
pre-calculus - Reiny, Friday, September 18, 2009 at 10:17pm
the standard equation of a circle with centre (h,k) and radius r is
(x-h)^2 + (y-k)^2 = r^2
so we ended up with
(x+4)^2 + (y-1)^2 = 25 or
(x+4)^2 + (y-1)^2 = 5^2
then the centre is (-4,1) and radius is 5
Here is an interesting page for your topic
pre-calculus - MUFFY, Saturday, September 19, 2009 at 10:45am
Thanks so much for your explanation. I was able to figure it out and now got your answer.
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