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October 1, 2014

October 1, 2014

Posted by **B.B.** on Friday, September 18, 2009 at 6:55am.

Give the solutions to the following quadratic equation by examining the graph of the related quadratic function:

Graph: y=x^2+2x-15

Equation: x^2+2x-15=0

Thanks so much.

- Math -
**Reiny**, Friday, September 18, 2009 at 7:33amalgebraic solution:

(x+5)(x-3) = 0

so x = -5 or x = 3

When you graphed it, did you not get a parabola that opened upwards and crossed the x-axis at -5 and 3 ?

- Math -
**drwls**, Friday, September 18, 2009 at 7:34amWe can't draw graphs for you; you can and should do that yourself.

Since the equation can be factored to (x+5)(x-3) = 0,

the solutions are x=-5 and +3.

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