Math
posted by B.B. .
I am stumped could someone please explain this problem?
Give the solutions to the following quadratic equation by examining the graph of the related quadratic function:
Graph: y=x^2+2x15
Equation: x^2+2x15=0
Thanks so much.

algebraic solution:
(x+5)(x3) = 0
so x = 5 or x = 3
When you graphed it, did you not get a parabola that opened upwards and crossed the xaxis at 5 and 3 ? 
We can't draw graphs for you; you can and should do that yourself.
Since the equation can be factored to (x+5)(x3) = 0,
the solutions are x=5 and +3.