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I am stumped could someone please explain this problem?
Give the solutions to the following quadratic equation by examining the graph of the related quadratic function:
Graph: y=x^2+2x-15
Equation: x^2+2x-15=0
Thanks so much.

  • Math -

    algebraic solution:
    (x+5)(x-3) = 0
    so x = -5 or x = 3

    When you graphed it, did you not get a parabola that opened upwards and crossed the x-axis at -5 and 3 ?

  • Math -

    We can't draw graphs for you; you can and should do that yourself.
    Since the equation can be factored to (x+5)(x-3) = 0,
    the solutions are x=-5 and +3.

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