Posted by erin on Thursday, September 17, 2009 at 6:35pm.
Draw the diagram. alternate the charges. With some thinking, you can see this is the only solution.
The two adjacent corners have an attractive net force, equal, so the resultant is toward the center:
Force= k2(cos45)2u*2u/3^2= 1.41k*2u*2u/9
Now the replelling force frm across the square is k2u*2u/(3sqrt2)^2= .5k(2u2u/9)
so the net force of attraction is...
(1.41-.5)k2u2u/9 N
dssax
find the resultant force on the charge at the center
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