I am stumped on this problem could someone please help?
Give the solutions to the following quadratic equation by examining the graph of the related quadratic function:
Graph: y=x^2+2x-15
Equation: x^2+2x-15=0
Thanks.
graph it. Look to see where the graph crosses the x axis, that is a "solution". A better word is "root".
To find the solutions to the quadratic equation x^2 + 2x - 15 = 0, you can examine the graph of the related quadratic function y = x^2 + 2x - 15.
Step 1: Plot the graph of the function y = x^2 + 2x - 15 on a coordinate plane. The graph should be a parabola.
Step 2: Look for the points where the graph intersects the x-axis. These points represent the solutions to the quadratic equation, as the y-coordinate of points on the x-axis is always zero.
Step 3: Read the x-coordinates of the points where the graph intersects the x-axis. These are the solutions to the quadratic equation.
In this case, the equation is already in standard form, so you can directly examine the graph:
Step 1: Plot the graph of the quadratic function y = x^2 + 2x - 15.
Step 2: Look for the points where the graph intersects the x-axis.
Step 3: Read the x-coordinates of those points.
By examining the graph, you can see that the graph intersects the x-axis at x = -5 and x = 3. These are the solutions to the quadratic equation x^2 + 2x - 15 = 0.
Therefore, the solutions to the quadratic equation are x = -5 and x = 3.