Posted by Joshua on Wednesday, September 16, 2009 at 3:56pm.
A Rock Is Thrown Vertically upward with a speed of 12m/s. Exactly 1.00s later a ball is thrown up vertically along the same path with a speed of 18m/s. At what time will they strike each other?
so far I got this but it does not seem to be working out for me.
G=9.80m/S^2
Y1=0+12m/s(T)+.5(G)T^2
Y2=0+18m/s(T1)+.5(G)(T1)^2
12m/s(T)+.5(G)T^2=18m/s(T1)+.5(G)(T1)
^2
I Cannt seem to get the right anwser of T=1.45s. What am I doing wrong?

Phyics  bobpursley, Wednesday, September 16, 2009 at 4:05pm
You have it set up correcty, except for signs.
12t4.9t^2=18(t1)4.9(t1)^2
12t4.9t^2=18t184.9(t^22t+1)
now combine terms, and solve.

Phyics  Joshua, Wednesday, September 16, 2009 at 4:16pm
Thank You not sure how i did catch that lol.
Answer This Question
Related Questions
 physics  two students are on a balcony 20.6 m above the street. One student ...
 physics  two students are on a balcony 20.6 m above the street. One student ...
 science  a ball is thrown straight upward and returns to the thrower's hand ...
 Physics  A rock is thrown vertically upward with a speed of 12.0 from the roof ...
 Physics  Two students are on a balcony a distance h above the S street. One ...
 physics  A ball is thrown vertically upward with an initial speed of 25 m/s. ...
 Physics  A ball is thrown vertically upward with an initial speed of 11 m/s . ...
 physics  A ball is thrown vertically upward with an initial speed of 20 m/s. ...
 physics  ll is thrown vertically upward with an initial speed of 16 m/s. Then, ...
 physics  ll is thrown vertically upward with an initial speed of 16 m/s. Then, ...
More Related Questions