Thursday
July 31, 2014

Homework Help: Phyics

Posted by Joshua on Wednesday, September 16, 2009 at 3:56pm.

A Rock Is Thrown Vertically upward with a speed of 12m/s. Exactly 1.00s later a ball is thrown up vertically along the same path with a speed of 18m/s. At what time will they strike each other?

so far I got this but it does not seem to be working out for me.
G=-9.80m/S^2
Y1=0+12m/s(T)+.5(G)T^2
Y2=0+18m/s(T-1)+.5(G)(T-1)^2

12m/s(T)+.5(G)T^2=18m/s(T-1)+.5(G)(T-1)
^2

I Cannt seem to get the right anwser of T=1.45s. What am I doing wrong?

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