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precalculus

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write an equation in general form...

the perpendicular bisector of the segment with endpoints at (2,-1) and (4,-5). I found the slope and then found the mid point and wrote to the equation and got X-2Y=3. But the answer is X-2Y=9...any help???

  • precalculus - ,

    slope is of the segment is -2, you got that correct, and slope of bisector is 1/2, right. The midpoint is at 3,-3

    y=mx+b
    -3=3/2 + b
    b= -4.5

    y=1/2 x -4.5
    2y=x-9
    x-2y=9

  • precalculus - ,

    The mid point of the segment is
    ((x1+x2)/2, (y1+y2)/2)=(3,-3)
    You have correctly calculated the slope m as 1/2.
    Using the equation
    (y-y1)=m(x-x1),
    we get
    (y-(-3))=(1/2)(x-3)
    2(y+3)=x-3
    x-2y=9
    You have probably mis-calculated the mid-point as (-3,-3)

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