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December 22, 2014

December 22, 2014

Posted by **kennedy** on Tuesday, September 15, 2009 at 6:32pm.

the perpendicular bisector of the segment with endpoints at (2,-1) and (4,-5). I found the slope and then found the mid point and wrote to the equation and got X-2Y=3. But the answer is X-2Y=9...any help???

- precalculus -
**bobpursley**, Tuesday, September 15, 2009 at 6:46pmslope is of the segment is -2, you got that correct, and slope of bisector is 1/2, right. The midpoint is at 3,-3

y=mx+b

-3=3/2 + b

b= -4.5

y=1/2 x -4.5

2y=x-9

x-2y=9

- precalculus -
**MathMate**, Tuesday, September 15, 2009 at 6:47pmThe mid point of the segment is

((x1+x2)/2, (y1+y2)/2)=(3,-3)

You have correctly calculated the slope m as 1/2.

Using the equation

(y-y1)=m(x-x1),

we get

(y-(-3))=(1/2)(x-3)

2(y+3)=x-3

x-2y=9

You have probably mis-calculated the mid-point as (-3,-3)

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