what are some point for the problem
y=1/2x+2
Are you looking for the location of the asymptotes?
i need like 4 coordinate poinst so i can graph it
The function
y=f(x)=1/(2x)+2
has interesting features near x=0 and y=2.
Make a table of values. You will probably need more than 4 points to graph it correctly. I would plot with more than 8 points.
Start with evaluating y for
x=-10,-2,-1,-0.1,0.1,1,2,10 and plot the graph.
so i can plot all of these for this solution
Yes, if you find that you need more points, by all means.
ook thanks
To find points on the graph of the equation y = (1/2)x + 2, you can assign values to x and solve for y.
Let's choose some values for x and calculate the corresponding values for y:
1. When x = 0:
Substitute x = 0 into the equation:
y = (1/2)(0) + 2
y = 0 + 2
y = 2
So, the point (0, 2) is on the graph.
2. When x = 2:
Substitute x = 2 into the equation:
y = (1/2)(2) + 2
y = 1 + 2
y = 3
So, the point (2, 3) is on the graph.
3. When x = -2:
Substitute x = -2 into the equation:
y = (1/2)(-2) + 2
y = -1 + 2
y = 1
So, the point (-2, 1) is on the graph.
You can continue this process to find more points by assigning different values to x and solving for y.