Posted by **physics** on Tuesday, September 15, 2009 at 4:16am.

At t= 0, a particle starts from rest at x= 0, y= 0, and moves in the xy plane with an acceleration ->a = (4.0ihat+ 3.0jhat)m/s^2. Assume t is in seconds.

Determine the position of the particle as a function of time t.

Express your answer in terms of the unit vectors ihat and jhat.

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