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August 28, 2014

August 28, 2014

Posted by **lina** on Monday, September 14, 2009 at 11:06pm.

Calculate the maximum height above the roof reached by the rock.

Calculate the magnitude of the velocity of the rock just before it strikes the ground.

Calculate the horizontal distance from the base of the building to the point where the rock strikes the ground.

- physics -
**drwls**, Tuesday, September 15, 2009 at 3:22amThe vertical component of velocity when the rock is thrown is 30 sin 42 = 20.07 m/s

Calculate the time T that it takes the rock to hit the ground using that initial velocity.

Hint: 20.07 T - (g/2) T^2 + 19.0 = 0

I assume you know what g is, and how to solve that quadratic equation. Take the positive root.

T times the horizontal velocity component is the horizontal distance that the rock travels.

The maximum height h of the rock is attained when the vertical velocity component is zero. This happens when

gt = 20.07 m/s

h = (1/2)(20.07 m/s)^2/g

Ebergy considerations can be used to compute the velocity at impact

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