Now the largest: Perimerter sum <150

150>4s+2w+2l
150>4s+2*3s + 2*(15-5s)
solve for s, then w, then l.

To solve the inequality 150 > 4s + 2w + 2l and find the values of s, w, and l, we need to isolate each variable.

First, simplify the equation:
150 > 4s + 6s + 30 - 10s

Combine like terms:
150 > 0s + 30

Now, subtract 30 from both sides of the equation:
150 - 30 > 0s + 30 - 30
120 > 0s

Since any number multiplied by 0 is always 0, the value of s doesn't affect the inequality. The inequality 120 > 0s is always true, as long as s is a real number.

Therefore, the value of s can be any real number.

Now, let's move on to finding the values of w and l.

From the original equation:
150 > 4s + 2w + 2l

Substituting the value of s with any real number, the equation becomes:
150 > 4(0) + 2w + 2l
150 > 2w + 2l

Now, let's isolate w and l by subtracting 2l from both sides:
150 - 2l > 2w + 2l - 2l
150 - 2l > 2w

Next, divide both sides by 2:
(150 - 2l)/2 > (2w)/2
75 - l > w

Lastly, rearrange the equation to get the values of w and l:
w < 75 - l
l > 75 - w

From these inequalities, we can see that w must be smaller than 75 minus the value of l, and l must be greater than 75 minus the value of w.

So to summarize:
- The value of s can be any real number.
- The value of w must be smaller than 75 minus the value of l.
- The value of l must be greater than 75 minus the value of w.