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February 28, 2015

February 28, 2015

Posted by **Roy** on Monday, September 14, 2009 at 9:23pm.

- Math -
**bobpursley**, Monday, September 14, 2009 at 9:35pmI see from the first statement that since the rectangle length is 15ft less than five times the sqare side, the square side cannot be less than 3.

lets make it 3.01 for the square. Now, the width of the rectangle then will be 3.01x3, or 9.03 width, and length .05.

So that is the smallest rectangle and the smallest square.

Now the largest: Perimerter sum <150

150>4s+2w+2l

150>4s+2*3s + 2*(15-5s)

solve for s, then w, then l.

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