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February 1, 2015

February 1, 2015

Posted by **projectile motion** on Monday, September 14, 2009 at 8:19pm.

The rock lands in a lake at the base of the cliff, a horizontal distance of 89.67 meters beyond the base of the cliff. How high is the cliff in meters?

Please explain steps and how to get there. please Thank you!!!

- physics -
**bobpursley**, Monday, September 14, 2009 at 8:30pmbreak the initial velocity into vertical and horizontal components with the sine and cosine.

horizontal distance=vihorz*time

solve for time in air.

in the vertical:

hfinal-hinitial= vivert*time-4.9t^2

solve for hfinal-hinitial.

- physics -
**projectile motion**, Monday, September 14, 2009 at 8:48pmi got an answer of y=-420.2599461m

is this right??

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