Posted by Emily on Monday, September 14, 2009 at 7:03pm.
I usually know how to do these types of problems, but the second variable just threw me off balance..
47. A rancher has 200 feet of fencing to enclose two adjacent rectangular corrals. What dimensions will produce a maximum enclosed area? (the diagram is of two adjacent corrals sharing a middle fence, y, and each individual corral has length x [so the two together would be 2x for the entire length])
I hope I've explained the diagram enough...any help is greatly appreciated!! :D

Precalculus  bobpursley, Monday, September 14, 2009 at 7:10pm
Fencing needed= 3Width + 4 length, correct? I don't have your diagram
Area= 2*W*L
so 200=3w+4L so l= (2003w)/4 putting that into area..
area= 2w(2004w)/4

Precalculus  Emily, Monday, September 14, 2009 at 8:18pm
Ohhhhhh i totally get it now! Thanks!! :D
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