Wednesday

November 26, 2014

November 26, 2014

Posted by **Emily** on Monday, September 14, 2009 at 7:03pm.

47. A rancher has 200 feet of fencing to enclose two adjacent rectangular corrals. What dimensions will produce a maximum enclosed area? (the diagram is of two adjacent corrals sharing a middle fence, y, and each individual corral has length x [so the two together would be 2x for the entire length])

I hope I've explained the diagram enough...any help is greatly appreciated!! :D

- Precalculus -
**bobpursley**, Monday, September 14, 2009 at 7:10pmFencing needed= 3Width + 4 length, correct? I dont have your diagram

Area= 2*W*L

so 200=3w+4L so l= (200-3w)/4 putting that into area..

area= 2w(200-4w)/4

- Precalculus -
**Emily**, Monday, September 14, 2009 at 8:18pmOhhhhhh i totally get it now! Thanks!! :D

**Answer this Question**

**Related Questions**

Algebra - A rancher wishes to enclose a rectangular partitioned corral with 1932...

math 099 - a rancher wants to use 300 feet of fencing to enclose a rectangular ...

Math - A rancher has 220 feet of fencing to enclose a rectangular corral. Find ...

College Algebra - A rancher wishes to enclose a rectangular partitioned corral ...

Precalculus - a farmer has available 1032 feet of fencing and wishes to enclose ...

Maths - A rancher wants to enclose a rectangular area and then divide it into ...

Calculus - A rancher wants to make an animal pen by fencing in an area of ...

Calculus - A cattle rancher wants to enclose a rectangular area and then divide ...

Precalculus - a farmer has available 1032 feet of fencing and wishes to enclose ...

Precalculus - a farmer has available 1032 feet of fencing and wishes to enclose...