trig please
posted by trig please on .
I have no idea how to do this
Find the value of the angle theta in degrees rounded to the neartest tenth of a degree.
I have no idea were to start...
h t t p : / / i m g 6 . i m a g e s h a c k . u s / i m g 6 / 5 8 9 9 / a d s f a s d f a s d f a d s f s a d f . j p g

the circles go to the top and there measurements i included in the pictures and there are right angles

if you don\'t understand the problem i tried to draw it in paint

Are you sure the 2 circles don't touch ?
If the do, it is an easy problem.
draw a line from the vertex through the two centres.
Let the distance between the vertex and the centre of the smaller circle be x
then the distance from the vertex to the centre of the larger circle is x+6
sin (theta/2) = 2/x
sin (theta/2) = 4/(x+6)
then 2/x = 4/(x+6)
which solves for x=6
then sin (theta/2) = 2/6
theta/2 = 19.47º
theta = 38.942º or 38.9º to the nearest tenth.