Monday

November 24, 2014

November 24, 2014

Posted by **trig please** on Monday, September 14, 2009 at 6:25pm.

Find the value of the angle theta in degrees rounded to the neartest tenth of a degree.

I have no idea were to start...

h t t p : / / i m g 6 . i m a g e s h a c k . u s / i m g 6 / 5 8 9 9 / a d s f a s d f a s d f a d s f s a d f . j p g

- trig please -
**trig please**, Monday, September 14, 2009 at 6:36pmthe circles go to the top and there measurements i included in the pictures and there are right angles

- Please -
**Please tell me**, Monday, September 14, 2009 at 7:00pmif you don\'t understand the problem i tried to draw it in paint

- trig please -
**Reiny**, Monday, September 14, 2009 at 8:05pmAre you sure the 2 circles don't touch ?

If the do, it is an easy problem.

draw a line from the vertex through the two centres.

Let the distance between the vertex and the centre of the smaller circle be x

then the distance from the vertex to the centre of the larger circle is x+6

sin (theta/2) = 2/x

sin (theta/2) = 4/(x+6)

then 2/x = 4/(x+6)

which solves for x=6

then sin (theta/2) = 2/6

theta/2 = 19.47º

theta = 38.942º or 38.9º to the nearest tenth.

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