A club has 32 members only 1/4 are boys. How many more boys would they need to have at least 1/3 boys if no more girls are added?
They must now have 8 boys. Agree?
to have 1/3 boys, after the 8
boys= 1/3 (32+x)
8+x= 1/3(32+x)
multiply bot sides by 3
24+3x=32+x
can you take it from here?
Here's one way to figure it out.
We know there are 8 boys in the club.
We're looking for a number larger than 32 that is evenly divisible by 3. But 33 doesn't work because 8 + 1 isn't 1/3 of 33.
The next number is 36. Try that one.
I hope a math tutor can post a better method for solving this problem.
I believe it is 2 and 1/3
To find out how many more boys the club needs to have at least 1/3 of its members as boys, we need to determine the number of members required for 1/3 to be boys.
Let's go step by step:
Step 1: Calculate the number of boys in the club (1/4 of the total membership)
The club has 32 members, and only 1/4 are boys. To find the number of boys, we can multiply the total number of members by 1/4:
32 * 1/4 = 32/4 = 8 boys
Step 2: Determine the desired percentage of boys
The question states that the club needs to have at least 1/3 of its members as boys. This means we want the boys to be 1/3 of the total membership, or 33.33% of the total.
Step 3: Calculate the desired number of boys
To calculate the desired number of boys, we need to find out 1/3 of the total membership.
32 * 1/3 = 32/3 ≈ 10.67
Step 4: Find the difference between the current number of boys and the desired number of boys
To find out how many more boys the club needs, we subtract the current number of boys (8) from the desired number of boys (10.67):
10.67 - 8 = 2.67
Therefore, the club would need approximately 2.67 (rounded to the nearest whole number) more boys to have at least 1/3 boys, assuming no more girls are added.