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April 20, 2014

April 20, 2014

Posted by **Pat** on Monday, September 14, 2009 at 1:22pm.

[2x / (3x (2nd power) - 5x - 2] + [(x-1) / (x (2nd power) -x - 20)]

- Algebra -
**Reiny**, Monday, September 14, 2009 at 2:44pmlet's write it this way

2x/(3x^2 - 5x - 2) + (x-1)/(x^2 -x - 20)

= 2x/[(3x+1)(x-2)] + (x-1)/[(x-5)(x+4)]

Your LCD is (3x+1)(x-2)(x-5)(x+4)

Unusual, as I had expected one of the factors to be the same in the denominators.

anyway...

[2x(x-5)(x+4) + (x-1)3x+1)(x-2)]/[(3x+1)(x-2)(x-5)(x+4)]

expand the top and collect like terms.

Good luck, since the result will certainly not be more simplified than the original.

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