physics
posted by Siphelo on .
A body starting from rest, travels a distance of 45 meters during the fifth second of motion.Calculate the acceleration of the body

v=u=at

d(6)d(5)= 45
1/2 a (6^25^2)=45
surely you can solve for a.
posted by Siphelo on .
A body starting from rest, travels a distance of 45 meters during the fifth second of motion.Calculate the acceleration of the body
v=u=at
d(6)d(5)= 45
1/2 a (6^25^2)=45
surely you can solve for a.