Posted by AP Physics B on Sunday, September 13, 2009 at 8:42pm.
Not if I understand what you did. a mass m1 was spun horizontally, and tied to a hanging mass m2. IF that is true, then
radial force=hanging force
m2 v^2/r=m1g
I dont understand what you did.
why would the hanging mass of a radial acceleration if it\'s just in equilibrium...???
m1 V^2/r = m2 g
I did this
net force = (m1 + m2) (radial acceleration of mass m1) = force of gravity on mass m2
What was the experiment setup? Was m1 rotating horizontally? Was m2 a hanging mass attacahed to the cord holding the rotating mass?
mass m1 was a robber stooper
m1 was attached to a string that went through a straw
on the other end of the straw the string came out and was attached to a mass m2
students spun mass m1 with hand on straw as the stopper spun around mass m2 the hanging mass was in equilibrium as mass m1 the stopper spun around in a circle and experienced a radial force
Then m2 was as I thought, it was supplying the tension counter centripetal force.
m2*g=m1*v^2/r
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