Posted by Physics on Sunday, September 13, 2009 at 6:18pm.
At t= 0, a particle starts from rest at x= 0, y= 0, and moves in the xy plane with an acceleration >a (vector) = (4.0ihat+ 3.0jhat)m/s^2. Assume t is in seconds.
Determine the x component of velocity as a function of time t.
Determine the y component of velocity as a function of time t.
Determine the speed of the particle as a function of time t.
Determine the position of the particle as a function of time t.

physics  drwls, Sunday, September 13, 2009 at 8:21pm
4.0 is the acceleration in the x direction (with the ihat unit vector)) and 3.0 is the acceleration in the y direction (with the jhat unit vector).
Vx = 4.0 t Vy = 3.0 t
V = sqrt(V2^2 + Vy^2) = 5 t
Integrate Vx and Vy for the x and y locations vs. t.

physics  How do you do this?, Monday, September 14, 2009 at 8:39pm
How would you integrate them?
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