physics
posted by Physics on .
At t= 0, a particle starts from rest at x= 0, y= 0, and moves in the xy plane with an acceleration >a (vector) = (4.0ihat+ 3.0jhat)m/s^2. Assume t is in seconds.
Determine the x component of velocity as a function of time t.
Determine the y component of velocity as a function of time t.
Determine the speed of the particle as a function of time t.
Determine the position of the particle as a function of time t.

4.0 is the acceleration in the x direction (with the ihat unit vector)) and 3.0 is the acceleration in the y direction (with the jhat unit vector).
Vx = 4.0 t Vy = 3.0 t
V = sqrt(V2^2 + Vy^2) = 5 t
Integrate Vx and Vy for the x and y locations vs. t. 
How would you integrate them?