Posted by Sandhu on Sunday, September 13, 2009 at 9:51am.
100.3 meters, if I'm not mistaken..
Well deep = 326/3.25= ~100m
Denote the height by h, and the time for stone to descend t, we have the equation
h=ut+(1/2)gt&sp2;
where
u=0 m/s, initiial speed, and
g=acceleration due to gravity.
For the sound to return, we have
h=326 m/s*(3.25-t)
Solve for h and t using the two equations.
You should have t=3.1 and h=47 m approximately
h=ut+(1/2)gt²
Thanks a lot
How exactly was h and t solved for?
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