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March 30, 2017

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A tennis ball is dropped from 1.41m above the ground. It rebounds to a height of 0.932 m.The acceleration of gravity is 9.8 m/s2 .(a)With what velocity does it hit the ground?(Let down be negative.) Answer in units of m/s. (b)With what velocity does it leave the ground? Answer in units of m/s. (c)If the tennis ball were in contact with the ground for 0.00575 s, find the acceleration given to the tennis ball by the ground. Answer in units of m/s2.
 

  • Physics - ,

    (c)
    Force = rate of change of momentum.
    Calculate the momentum change, divide by the contact duration, you will get the acceleration, after the mass cancels out.
    It will be a huge number over 1600 m/s/s.
    See also following link for your reading:
    http://www.vias.org/physics/example_2_5_13.html

  • Physics - ,

    i need help too

  • Physics - ,

    Boop

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