Calculate the acceleration due to gravity on the moon. The moon\'s radius is about 1.74 E 6 m and its mass is 7.35 E 22 kg
ok aparently there\'s an easier way to do this
I applied Newtons second law in the radial direction
net force radial = m (radial acceleration) = Fg
were Fg is r^-2 G m m2
I solved for the period then calculated the acceleration to be
5.91 E 18 s^-3 m
how do I do this because I just assumed that it was the Earth\'s moon which... isn\'t necissarily true and i used the mass of the earth which wasn\'t given in the problem i used 5.98 E 24 kg for mass of earth
what is the easy way to do this...
my teacher told me
Little g is the force of gravity (weight) divided by the mass of the object that’s feeling the force. Another way to look at it: little g helps find the force a single kilogram of mass would feel. It describes the force per unit mass. You could say that g = W/m (which makes sense, when you consider that W = mg).
not exactly sure what the heck it\'s talking about because Fg or in that case weight is not equal to mg
acceleartiononmoon= GMassmoon/radius^2
=G 7.35E22/(1.74E6)^2= G 2.43E10=
= 6.67E-11*2.43E10=
1.62 m/s^2 or as a gravitational field constant= 1.62 N/kg
I have no idea why you used the mass of Earth.
To calculate the acceleration due to gravity on the moon, you can use the equation:
g = G (M/r^2)
where g is the acceleration due to gravity, G is the gravitational constant (approximately 6.674 × 10^-11 m^3/kg/s^2), M is the mass of the moon, and r is the radius of the moon.
Given that the moon's radius (r) is about 1.74 × 10^6 m and its mass (M) is about 7.35 × 10^22 kg, we can substitute these values into the equation:
g = (6.674 × 10^-11 m^3/kg/s^2) * (7.35 × 10^22 kg) / (1.74 × 10^6 m)^2
Simplifying this calculation will give the acceleration due to gravity on the moon.
To calculate the acceleration due to gravity on the moon, you can use the formula g = Fg/m, where g represents the acceleration due to gravity, Fg is the force of gravity, and m is the mass of the object. In this case, we are interested in finding the acceleration due to gravity on the moon's surface.
Using Newton's law of universal gravitation, we can calculate the force of gravity between two objects with masses m1 and m2 and a distance r between their centers:
Fg = (G * m1 * m2) / r^2,
where G is the gravitational constant.
In this question, we have the mass of the moon (m1) and the radius of the moon (r). We can assume that the mass of the object feeling the force (m2) is 1 kg.
Now, we substitute the values in the formula:
Fg = (G * m1 * m2) / r^2.
Fg = (6.67 E-11 N(m^2/kg^2) * 7.35 E 22 kg * 1 kg) / (1.74 E 6 m)^2.
After performing the calculation, you'll find the value of Fg, which is the force of gravity between the moon and a 1 kg object.
To find the acceleration due to gravity (g), divide Fg by the mass of the object (1 kg):
g = Fg / m.
g = (Fg) / (1 kg).
By performing this final calculation, you'll obtain the acceleration due to gravity on the moon's surface, expressed in m/s^2.
It's important to note that the value of g will be less than the acceleration due to gravity on Earth (9.8 m/s^2) since the moon is less massive than Earth and has a smaller radius.