Posted by Hannah on Saturday, September 12, 2009 at 1:31pm.
Suppose the position of an object is given by >r(vector) = (3.0t^2*ihat  6.0t^3*jhat)m. Where t in seconds.
Determine its velocity >v as a function of time t.
Determine its acceleration >a as a function of time t.
Determine >r at time t = 2.5 s.
Determine >v at time t = 2.5s.
Express your answer using two significant figures. Express your answer in terms of the unit vectors ihat and jhat.

Physicscalc  MathMate, Saturday, September 12, 2009 at 5:33pm
This is a problem of differentiation where the independent variable is t, and
r is the position vector.
v is the velocity vector.
a is the acceleration vector.
The motion is described in two orthogonal directions i and j, which means that you can do the calculations in each of the directions independently of each other.
Given
r = (3.0t^2i  6.0t^3j) m
The i and j components of the position vector are
Pi(t)=3.0t^2
Pj(t)=6.0t^3
So d(Pi(t))/dt = d(3t²)/dt = 6t
...
can you complete the rest?
Post your answers for a check if you wish to.

Physicscalc  Hannah, Saturday, September 12, 2009 at 6:56pm
What it P representing? Position?

Physicscalc  Kim, Thursday, February 18, 2016 at 6:13pm
6t18t
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