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A shot-putter throws the shot (mass = 7.3kg) with an initial speed of 15.0 m/s at a 33.0 degree angle to the horizontal.
Calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.00m above the ground.

  • Physics - ,

    no air resistance?

    consider the horizonal distance:
    d= Vihorizontal*time = 15cos33*t
    now the vertical:
    finalheight=initialheight+ vivertical*t- 4.9t^2
    0=2+15sin33 t - 4.9 t^2
    solve the second equation for time. Use the quadratic equation. Put that time t into the first equation (distance horizontal).

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