Posted by **Andy** on Friday, September 11, 2009 at 11:29pm.

A Hollywood Daredevil plans to jump a canyon on a motorcycle. There is a 15 m drop and the horizontal distance originally planned was 60 m but it turns out the canyon is really 69.6 m across. If he desires a a 3.2 second flight time

a. what is the correct angle of his launch ramp?

b.what is his correct launch speed?

c.what is the correct angle for the landing ramp?

d.what is his predicted landing velocity?

- physics -
**drwls**, Saturday, September 12, 2009 at 1:19am
a. The 3.2 s flight time tells you what the vertical launch component, Vy, must be.

Vy*3.2 s - g*(3.2)^2/2 = -15

Vy = 7.87 m/s

The width of the canyon and the flight time tell you what the horizontal velocity component, Vx, must be

Vx*3.2s = 69.6 m

Vx = 21.75 m/s

The ratio Vy/Vx is the tangent of the launch angle.

b. V = sqrt (Vx^2 + Vy^2)

c. Calculate the final vertical velocity at landing. It will be larger than the launch value of Vy because of the loss of height. Vy(final)/Vx will be the landing ramp angle tangent.

d. You can get this easily from the launch velocity and the 15 meter drop in altitude. V^2 increases by 2 g H, where H = 15 m.

## Answer this Question

## Related Questions

- physics - A Hollywood Daredevil plans to jump a canyon on a motorcycle. There ...
- physics - A Hollywood Daredevil plans to jump a canyon on a motorcycle. There ...
- Physics - A Hollywood daredevil plans to jump the canyon shown in the figure on ...
- Physics - A Hollywood daredevil plans to jump the canyon shown in the figure on ...
- Physics - A daredevil decides to jump across a 15 m wide canyon on his ...
- Physics - A daredevil decides to jump a canyon of width 10 m. To do so, he ...
- Physics - A daredevil decides to jump a canyon of width 10 m. To do so, he ...
- physics - A daredevil decides to jump a canyon of width 12 m. To do so, he ...
- Physics - A daredevil decides to jump a canyon of width 6.5 m. To do so, he ...
- physics - A daredevil decides to jump a canyon of width 8.4 m. To do so, he ...