suppose there is a 3-degree drop in temperature for every thousand feet that an airplane climbs into the sky.If the temperature on the ground which is at sea level is 63 degrees what would be the temperature when the plane reaches an altitude of 30,000 ft.

As Bobpursley recommended in the last post, please show your work and then we can help you find any mistakes.

http://www.jiskha.com/display.cgi?id=1252687958

To calculate the temperature when the plane reaches an altitude of 30,000 feet, we can use the given information that there is a 3-degree drop in temperature for every thousand feet that the airplane climbs.

First, let's calculate how many thousands of feet are present in 30,000 feet:

30,000 feet ÷ 1,000 = 30 thousands of feet

Next, we can calculate the temperature drop by multiplying the number of thousands of feet by the drop rate per thousand feet.

30 (thousands of feet) × 3 (degree drop per thousand feet) = 90 degrees drop

Now, we can subtract the temperature drop from the ground temperature to find the temperature at 30,000 feet:

63 degrees - 90 degrees = -27 degrees

Therefore, the temperature when the plane reaches an altitude of 30,000 feet would be -27 degrees Fahrenheit.

show your thinking. I think your are mooching for answers. I already outlined this for you.