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January 31, 2015

January 31, 2015

Posted by **Dean** on Thursday, September 10, 2009 at 10:34pm.

Hi, I'm stuck on these problems, and I asked my family members, they don't know, so I've come to you, community! Please help, thanks.

Directions:

Round each decimal to the underlined place-value position.

4.2974

(seven is the underlined number)

39.987

(nine is the underlined number.)

0.085

(zero is the underlined number)

Thanks, just three questions from my homework and hopefully I can manage the rest of it.

- 7th Grade Math -
**Ms. Sue**, Thursday, September 10, 2009 at 10:39pm4.2974 = 4.297

39.987 = 40.0

0.085 = 0.1

- 7th Grade Math -
**Kerri**, Thursday, September 10, 2009 at 10:41pmIf the number on the right side is lower than 5 then the (underlined) number stays the same and if the number on the right is 5 or higher then the underlined number goes up one

- 7th Grade Math -
**Kerri**, Thursday, September 10, 2009 at 10:42pmthe number on the right side of the underlined number***

- 7th Grade Math -
**Dean**, Thursday, September 10, 2009 at 10:45pmThank you

- 7th Grade Math -
**Erika**, Friday, September 11, 2009 at 12:10amHi. I'm in 7th grade too. Look to the right of the underlined number. Determine if it is between 0-4 or 5-9. If it is in the category 0-4 keep the number the same.

If it's in between 5 and 9, round it up to the next number in the number line. EX: 2.15 underlined is 1...you would round it to 2.2 I hope this helps!

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