Does this:

sqrt 3x-4=(x-4)^2-3

Multiply out to:

x^4-16x^3+90^2-211x+173

I then need to put it in the graphing calc and see what the roots are.

don't repeat the same question more than once.

Look back at your previous post to see if somebody has answered it.

http://www.jiskha.com/display.cgi?id=1252627992

Someone did answer it, however, I believe that their answer is incorrect. Also, I changed my answer a bit. I'm sorry, I messed up but I am becoming very frustrated with this problem.

Please disregard, I found your answer.

To determine if the given equation

sqrt(3x - 4) = (x - 4)^2 - 3

multiplies out to

x^4 - 16x^3 + 90x^2 - 211x + 173,

we need to follow a step-by-step process. Let's break down the steps for you:

1. Start with the given equation:

sqrt(3x - 4) = (x - 4)^2 - 3

2. Square both sides of the equation to eliminate the square root:

(sqrt(3x - 4))^2 = ((x - 4)^2 - 3)^2

Simplifying gives:

3x - 4 = (x - 4)^4 - 6(x - 4)^2 + 9

3. Next, expand the right side by squaring the binomial:

3x - 4 = (x^2 - 8x + 16)^2 - 6(x^2 - 8x + 16) + 9

Expanding further, we get:

3x - 4 = x^4 - 16x^3 + 90x^2 - 220x + 169

4. Comparing the equation obtained in step 3:

3x - 4 = x^4 - 16x^3 + 90x^2 - 220x + 169

with the equation mentioned in your question:

x^4 - 16x^3 + 90x^2 - 211x + 173

We can observe that there's a slight difference between the two equations. The constant term (the term without any x) differs.

The given equation doesn't multiply out to x^4 - 16x^3 + 90x^2 - 211x + 173. There might be a mistake somewhere in the calculations or the equation given.

5. Finally, if you were to graph the equation x^4 - 16x^3 + 90x^2 - 211x + 173 on a graphing calculator, you can find the roots or the x-values where the equation evaluates to zero. The roots represent the points on the x-axis where the equation intersects it.