Calculus
posted by Jenna on .
We're doing a lab in my Calc II class and I'm stuck on this question. I tried to do it by looking at instructions for a similar question in the book, but it made me more confused. Here is the question and my work:
Find the area of the region enclosed by the lines and curves:
x(y^2)=0 and x+2(y^2)=3
Here is my work:
x= (y^2) and x= 32(y^2)
(y^2)= 32(y^2)
3(y^2)3=0
3((y^2)1)=0
3(y+1)(y1)=0
y=1, 1
That's following what the book showed my to do. However, the book used those y values as the upper and lower bounds of the integral, but by looking at the graph that doesn't make any sense. If I used those as the upper and lower bounds, the answer I got was 4 units^2. How do I do this problem?

I still keep getting 4. At this step:
area= int (32y^2y^2) dy
= int (3(y^21) dy
shouldn't it be int(3(1y^2)?
I did this:
3int(dy)3int(y^2)dy= 3y (3(y^3)/3) = 3y(y^3) from 1 to 1... filling those in, I get 4. Am I still making a mistake?