Posted by **Jenna** on Thursday, September 10, 2009 at 7:39pm.

We're doing a lab in my Calc II class and I'm stuck on this question. I tried to do it by looking at instructions for a similar question in the book, but it made me more confused. Here is the question and my work:

Find the area of the region enclosed by the lines and curves:

x-(y^2)=0 and x+2(y^2)=3

Here is my work:

x= (y^2) and x= 3-2(y^2)

(y^2)= 3-2(y^2)

3(y^2)-3=0

3((y^2)-1)=0

3(y+1)(y-1)=0

y=-1, 1

That's following what the book showed my to do. However, the book used those y values as the upper and lower bounds of the integral, but by looking at the graph that doesn't make any sense. If I used those as the upper and lower bounds, the answer I got was 4 units^2. How do I do this problem?

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