remember log a- log b= log(a/b)
so with that..
then solve for x.
log_4[x] - log_4[x-1] = 1/2 implies log_4[x/(x-1)] = 1/2 which means that 4^(1/2) = x/(x-1) or, 2 = x/(x-1). I shall assume you can finish from there.
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