The ladle at an iron foundry can hold 8500 kg of molten iron; 646 metric tons of iron are needed to make rails. How many ladlefuls of iron will it take to make 646 metric tons of iron? (1 metric ton=1000 kg)
646 mtons x (1000 kg/1 mton) x (1 ladleful/8500 kg) = ?? ladlefuls. Check my thinking. Make sure the units we don't want cancel to leave just ladlefuls.
The ladle at an iron foundry can hold 8500 kg of molten iron. You need 646 metric tons of iron to make rails. How many ladlefuls of iron will it take to make 646 metric tons of iron? (note - 1 metric ton = 1000 kg
To find out how many ladlefuls of iron are needed to make 646 metric tons, we need to convert the metric tons to kilograms.
1 metric ton = 1000 kg
So, 646 metric tons = 646 * 1000 = 646,000 kg
Now, let's calculate the number of ladlefuls:
Each ladle can hold 8500 kg of molten iron.
Number of ladlefuls = Total amount of iron needed / Amount of iron per ladle
Number of ladlefuls = 646,000 kg / 8500 kg
Number of ladlefuls = 76
Therefore, it will take 76 ladlefuls of iron to make 646 metric tons of iron.
To determine how many ladlefuls of iron it will take to make 646 metric tons of iron, we need to find the number of ladles required per metric ton and then multiply it by the number of metric tons needed.
1 metric ton is equal to 1000 kg, so 646 metric tons will be equal to 646,000 kg.
Given that the ladle can hold 8500 kg of molten iron, we can divide the total amount needed (646,000 kg) by the capacity of the ladle (8500 kg) to find the number of ladlefuls required:
Number of ladlefuls = 646,000 kg ÷ 8500 kg/ladle
Number of ladlefuls ≈ 75.88 ladlefuls
Therefore, it will take approximately 75.88 ladlefuls of iron to make 646 metric tons of iron.