Write in standard form an equation of the line with the given slope through the given point: slope = -4;(2,2)
y-y1=m(x-x1)
y=4x+10
4x+y=10
i think this is correct
Thank you!
:D
To write the equation of a line in standard form, we need to express it in the form: Ax + By = C, where A, B, and C are integers and A is positive (non-negative).
Given a slope of -4 and a point (2,2), we can use the point-slope form of a linear equation to find the equation of the line. The point-slope form is given by: y - y1 = m(x - x1), where (x1, y1) are the coordinates of the given point, and m is the slope.
Using the given slope of -4 and the point (2, 2), we have:
y - 2 = -4(x - 2)
Now, we simplify the equation:
y - 2 = -4x + 8
Next, we can rearrange the equation to express it in standard form:
4x + y = 2 + 8
Simplifying further, we get:
4x + y = 10
Therefore, the equation of the line in standard form with a slope of -4 through the point (2, 2) is 4x + y = 10.