Algebra 1
posted by Samantha on .
Lately I just have blacked out in my algebra 1 class. Here's a equation on my worksheet, and I would be happy if you could show in steps how you got your answer. Thank you.
(2x²+5x+3)(x²+2x+1)

this is not an equation, it probably says to "simplify" it.
(2x²+5x+3)(x²+2x+1)
how about pretending to see it as :
1(2x²+5x+3)1(x²+2x+1) , then
= 2x²+5x+3x²2x1
= x²+3x+2 
Yes it does say simplify it, I'm sorry. I understand how you got that, but what if I had something like this.
4x2xy+3x²+y+5xy+x²y 
You start by ordering the terms. The priority of ordering is
1. name of variable in alphabetical order.
For example, put 2xy before y²
2. power of variable in descending order.
Example: x²y is placed before xy²
3. The constant term will be placed at the end.
After that, you would have collected like terms together. Add/subtract like terms. For example, 2x²y + 4x²y = 6x²y.
For 4x2xy+3x²+y+5xy+x²y
Ordering gives
3x² + x²y + 4x + 5xy  2xy + y
Add like terms, if any (5xy2xy=3xy)
3x² + x²y + 4x + 3xy + y
That is all you can do. You cannot add/subtract unlike terms.
x²y and 2yx² are like terms.
xy and 3x² are unlike terms.