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Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train B is traveling at 60 miles per hour. Train A passes a station at 8:25 p.m. If train B passes the same station at 8:37 p.m. at what time will train B catch up to train A?

  • algebra -

    Let the time between 8:25 and the moment they meet be t hours

    So train B covers the distance from the station to where they meet in 12 minutes less than train A
    and 12 minutes = 12/60 or .2 hours

    then 60t = 40(t + .2)
    solve for t, you should get t=.4hours
    which is the same as .4(60) minutes or 24 minutes.

    so they will meet at 8:49 pm

  • correction -algebra -

    I just looked at my definition of t again and according to my equation should have defined it as

    Let the time between 8:37 and the moment they meet be t hours

    I should then have added the 24 minutes to 8:37 to get a time of

    9:01 pm

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