Posted by Cassandra on Tuesday, September 8, 2009 at 3:41am.
So there are two steps since two accelerations are involved.
Step 1: acceleration = +12 m/s/s
initial velocity, u=0
final velocity = v
distance travelled, S=28 m
using
V²-u²=2aS
we find
v²
=2aS+u²
=2*12*28+0
=4√42 m/s (upwards)
=25.92 m/s (upwards)
Step 2: free fall, a=-9.81 m/s/s
initial velocity, u = 4√42 m/s
distance travelled, S = -28 m
final velocity = v
Again, we use the formula
V²-u²=2aS
from which
v²
=2aS+u²
=2*(-9.81)*(-28)+(4√42)²
=1221.36
v=√1221.36
=34.95 m/s (downwards)
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