Post a New Question


posted by on .

Air resistance acting on a falling body can be taken into account by the approximate relation for the acceleration:

a=dv/dt=g-kv where k is constnat

Derive a formula for the velocity of the body as a function of time assuming it starts from rest (v=0 at t=0)


  • calc - ,

    Integral of dv/(g - kv) = integral of dt
    Integrate both sides, from time from 0 to t; and v from 0 to v, for an equation for t in terms of v. Then invert the equation for v(t)

  • calc - ,

    It would be great to see how this is done. The prof's way of doing it is way confusing and intricate and I just started learning integrals.

  • calc - ,

    This is why you'd need to do exercises in integration.
    To give you a hint,
    ∫dv/(g-kv) = -log(g-kv)/k
    This could be inferred from standard integrals:
    ∫dx/(a+bx) = (1/b)log(a+bx)

  • calc - ,

    I agree. I suspect the Prof's method is confusing because you don't understand learn by experience spaced over time. There is no substitute in calculus for hump, grunt, and strain...that is, practice, trial and error.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question