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August 1, 2014

August 1, 2014

Posted by **Cara** on Tuesday, September 8, 2009 at 1:15am.

How far above the base of the cliff does this happen in meters?

- Physics ?#2 -
**drwls**, Tuesday, September 8, 2009 at 1:44amWrite equations for the heights of each ball vs time and set them equal. Solve the resulting equation for time. Then compute the vertical height at that time.

y1 = 53.0 - 4.9 t^2

y2 = 25 t - 4.9 t^2

y2 - y1 = 0 = 25 t - 53

t = 53/25 s = 2.12 s

y1 = 31.0 m

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