You've just prepared a solution by transferring 20.0 g of glucose into a 1.0 - L volumetric flask, and adding water to the mark. Calculate the concentration of the glucose solution in terms of millimoles/Liter, mg/mL, and % (m/v).

Ok, I think i'm overwhelmed by the wordinng of this question. Do you just convert g to millimoles to get millimoles/Liter, and then grams to mg and liters to mL to get mg/mL? And the same with the last one? What is v?

yes, yes, and yes.

%(m/v) means percent mass/volume. That means grams solute/100 mL solution.

To find the concentration of the glucose solution in terms of millimoles per liter (mmol/L), we need to convert the mass of glucose to millimoles and divide it by the volume of the solution.

First, let's convert grams of glucose to millimoles. To do this, we need to know the molar mass of glucose, which is approximately 180.16 g/mol.

20.0 g of glucose / (180.16 g/mol) = 0.111 mmol

Next, we divide the number of millimoles by the volume of the solution to find the concentration in mmol/L:

0.111 mmol / 1.0 L = 0.111 mmol/L

So, the concentration of the glucose solution in terms of millimoles per liter is 0.111 mmol/L.

Now, let's calculate the concentration in milligrams per milliliter (mg/mL). We can convert grams of glucose to milligrams and liters of solution to milliliters:

20.0 g of glucose = 20,000 mg
1.0 L = 1000 mL

20,000 mg / 1000 mL = 20 mg/mL

Therefore, the concentration of the glucose solution in milligrams per milliliter is 20 mg/mL.

Lastly, let's calculate the concentration as a percentage by mass (% m/v). In this case, "v" refers to the volume of the solution.

To calculate % m/v, we divide the mass of glucose by the volume of the solution and multiply by 100:
(20.0 g / 1.0 L) * 100 = 2% m/v

Thus, the concentration of the glucose solution is 2% (m/v).