Posted by
**Anonymous** on
.

What is the equation of a circle with its center at (0,3) and a diameter of 6.

Answers:

a. x^2+(y+3)^2=9

b. x^2-(y-3)^2=9

c. x^2+y^2-6y=0

d. x^2+(y_3)^2=0

e. x^2+(y-3)^2=36

Tuesday

March 28, 2017
Posted by
**Anonymous** on
.

What is the equation of a circle with its center at (0,3) and a diameter of 6.

Answers:

a. x^2+(y+3)^2=9

b. x^2-(y-3)^2=9

c. x^2+y^2-6y=0

d. x^2+(y_3)^2=0

e. x^2+(y-3)^2=36

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