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October 20, 2014

October 20, 2014

Posted by **Autumn** on Monday, September 7, 2009 at 8:46pm.

Please help!!!!!!

P.S. please don't round your numbers till the final answer, so there are no rounding errors, and please round the final number to 4 significant figures.

Do you need the degrees to solve this problem?? Alos please, if you are so kind explain step by step as to how to solve this problem.

thank you

- Physics -
**MathMate**, Tuesday, September 8, 2009 at 8:40amThe best way to solve this type of problems is by a table of component vectors.

Let x- and y-axes represent east and north respectively.

Resolve each segment of the trip into the x- and y-components.

Add up vectorially the components, which is the resultant displacement.

If the displacement is (x,y), the magnitude is √(x²+y²).

Work in hours, i.e. minutes should be divide by 60.

Distance x-component y-component

59.78 59.78*cos(0) 59.78*sin(0)

89.67 89.67*cos(90) 89.67*sin(90)

29.89 29.89*cos(270-59.78) 29.89*sin(270-59.78)

--------------------------------------

sum x y

Find (x,y), and the magnitude of displacment is √(x²+y²)

Divide the magnitude of displacement by the time (in hours) will give you the average velocity in miles per hour.

Post your answer for verification if necessary.

- Physics -
**Autumn**, Tuesday, September 8, 2009 at 9:59pmi got 16.46 mi/hr. is that right??

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