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November 29, 2014

November 29, 2014

Posted by **Ray** on Monday, September 7, 2009 at 6:21pm.

(a) How deep is the lake?

1Your answer is incorrect. m

(b) What is the average velocity of the ball?

2Your answer is incorrect. m/s

(c) Suppose that all the water is drained from the lake. The ball is now thrown from the diving board so that it again reaches the bottom in 4.98 s. What is the initial velocity of the ball?

- Physics -
**MathMate**, Tuesday, September 8, 2009 at 8:22amConsider the free fall height of S=-5.42 m.

Initial velocity u=0 m/s.

Final velocity = v.

Acceleration due to gravity, g=-9.81 m/s/s

Use the relation

v²-u² = 2aS

to get

v=sqrt(2*(-9.81)*(-5.42)+0)

=10.312 m/s

The time required for the drop (to the surface of the lake)

= 10.312/9.81 m/s / m/s/s

= 1.051 seconds

There is enough information to complete the calculations. Post your work any time if you encounter problems.

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