Posted by Ray on Monday, September 7, 2009 at 6:21pm.
Consider the free fall height of S=-5.42 m.
Initial velocity u=0 m/s.
Final velocity = v.
Acceleration due to gravity, g=-9.81 m/s/s
Use the relation
v²-u² = 2aS
to get
v=sqrt(2*(-9.81)*(-5.42)+0)
=10.312 m/s
The time required for the drop (to the surface of the lake)
= 10.312/9.81 m/s / m/s/s
= 1.051 seconds
There is enough information to complete the calculations. Post your work any time if you encounter problems.
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